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依次采用磷酸盐缓冲液(PBS)和甲醇-PBS溶液提取样品,以多功能免疫亲和柱净化,采用液相色谱-串联四极杆质谱检测,可同时测定中药材中的黄曲霉毒素B1、黄曲霉毒素B2、黄曲霉毒素G1、黄曲霉毒素G2、伏马毒素B1、伏马毒素B2、T-2毒素、HT-2毒素、赭曲霉毒素A(OTA)、玉米赤霉烯酮等14种真菌毒素.优化条件下,真菌毒素的定量限(LOQ)为1~5μg/kg,4种中药材基质(人参、桔梗、板蓝根、麦门冬)中3个不同添加水平的平均回收率(n=6)为71.9%~99.7%,相对标准偏差(RSD)为4.8%~15.8%.该方法的检测速度快,中药材复杂基质的干扰较少,结果准确、可靠,定量限可满足国内外中药材真菌毒素相关限量的要求.

参考文献

[1] Yang J B.Chinese Journal of Endemiology(杨建伯.中国地方病学杂志),2002,21(4):314
[2] Chen L X.Hebei Journal of Industrial Science & Technology (陈丽星.河北工业科技),2006,23(2):124
[3] Huang L,Zhang H,Ding W Q,et al.Strait Pharmaceutical Journal(黄莉,张浩,丁伟琴,等.海峡药学),2009,21(6):95
[4] Tang Y.Chinese Journal of Chinese Materia Medica (汤扬.中国中药杂志),2000,25(7):437
[5] Kuang P L.Chinese Traditional Patent Medicine(匡佩琳.中成药),2000,22(7):478
[6] Liang Y Q,Huang R F.Chinese Journal of Modern Applied Pharmacy(梁月秋,黄荣芳.中国现代应用药学杂志),2000,17(3):224
[7] Yang M H,Chen J M,Zhang X H.Chromatographia,2005,62(9):499
[8] Romagnoli B,Menna V,Gruppioni N,et al.Food Control,2007,18(6):697
[9] Tassaneeyakul W,Razzazi-Fazeli E,Porasuphatana S,et al.Mycopathologia,2004,158(2):239
[10] Thirumala-Devi K,Mayo M A,Reddy G,et al.Food Addit Contam,2001,18(9):830
[11] Ari(n)o A,Herrera M,Estopa(n)an G,et al.Intern J Food Micro,2007,114(3):366
[12] Sewram V,Shephard G S,van der Merwe L,et al.J Agric Food Chem,2006,54(15):5688
[13] Trucksess M W,Scott P M.Food Addit Contam,2008,25(2):181
[14] Zheng R,Mao D,Wang S M,et al.Chinese Journal of Pharmaceuticals(郑荣,毛丹,王少敏,等.中国医药工业杂志),2010,41(5):368
[15] Han Z,Zheng Y L,Luan L J.Anal Chim Acta,2010,664(2):165
[16] Meng J,Zhang J,Zhang N,et al.Chinese Journal of Chromatography(孟娟,张晶,张楠,等.色谱),2010,28(6):601
[17] Commission Decision of 12 August 2002 Implementing Council Directive 96/23/EC Concerning the Performance of Analytical Methods and The Interpretation of Results (2002/657/EC).(2002-08-17)[2010-12-13].http://eurlex.europa.eu/LexUriServ/LexUriServ.do? uri= OJ:C:2002:192:0005:0008:EN:PDF
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