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采用忆阻器替换分段线性电阻的方法,在Matsumoto,Chua和Kobayashi (MCK)提出的四阶混沌电路基础上,设计了一个含有忆阻器的五阶对称混沌电路,建立了五阶忆阻混沌电路的数学模型.采用常规动力学分析方法,分析了五阶忆阻混沌电路的平衡点集及其稳定性、Lyapunov指数.采用常规元器件,构建了五阶忆阻混沌电路的仿真模型,并进行了电路仿真实验.理论分析和仿真实验结果表明,设计的五阶忆阻混沌电路具有丰富的混沌行为,丰富了忆阻混沌电路的设计与应用.

参考文献

[1] Strukov,DB;Snider,GS;Stewart,DR;Williams,RS.The missing memristor found.[J].Nature,20087191(7191):80-83.
[2] Banerjee, T..Single amplifier biquad based inductor-free Chua's circuit[J].Nonlinear dynamics,20124(4):565-573.
[3] Bayat, F. Merrikh;Hoskins, B.;Strukov, D. B..Phenomenological modeling of memristive devices[J].Applied physics, A. Materials science & processing,20153(3):779-786.
[4] Batas, D.;Fiedler, H..A Memristor SPICE Implementation and a New Approach for Magnetic Flux-Controlled Memristor Modeling[J].IEEE transactions on nanotechnology,20112(2):250-255.
[5] Chul-Moon Jung;Kwan-Hee Jo;Kyeong-Sik Min.SPICE Macromodel and CMOS Emulator for Memristors[J].Journal of nanoscience and nanotechnology,20122(2):1487-1491.
[6] Chua, L..Resistance switching memories are memristors[J].Applied physics, A. Materials science & processing,20114(4):765-783.
[7] Memristive circuits simulate memcapacitors and meminductors[J].Electronics Letters,20107(7):517.
[8] Riaza, R..Nondegeneracy Conditions for Active Memristive Circuits[J].IEEE Transactions on Circuits and Systems, II. Express briefs,20103(3):223-227.
[9] Muthuswamy, B.;Chua, L.O..Simplest chaotic circuit[J].International journal of bifurcation and chaos in applied sciences and engineering,20105(5):1567-1580.
[10] Muthuswamy, B..Implementing memristor based chaotic circuits[J].International journal of bifurcation and chaos in applied sciences and engineering,20105(5):1335-1350.
[11] 套格图桑;伊丽娜.非线性LC电路方程的多种新解[J].量子电子学报,2015(1):30-39.
[12] 何玉俊;褚润通;李凡.周期振子Chua电路的线性耦合同步[J].量子电子学报,2013(5):601-607.
[13] 包伯成;刘中;许建平.忆阻混沌振荡器的动力学分析[J].物理学报,2010(6):3785-3793.
[14] 欧青立;徐兰霞.一个新的多涡卷混沌系统及其电路仿真[J].计算机工程与应用,2013(12):187-190.
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