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本文研究了非晶态(Fe_(1-x)Co_x)_(78)Si_(9.5)B_(12.5)合金的饱和磁化强度与温度的关系以及室温下的M()ssbauer谱。得到每个过渡金属原子的磁矩从x=0时的2.1μ_B下降到x=1.0时1.2μ_B。Curie温度T_C与成分的关系可用分子场近似来描述。平均超精细场从x=0时的250kOe增加到x=0.7时的278.5kOe,然后在x=0.9时下降到262kOe。假定每个Co原子的磁矩不随成分而变化(1.2μ_B),得出每个Fe原子的磁矩μ_(Fe)随x的增加而增加并逐渐趋近饱和值2.6μ_B(x=0.9)。平均超精细场(h)_f和平均磁矩(■)可表示为:(h)_f/(■)=h_0+h_1μ_(Fe)/(■),用最小二乘法得到系数h_0和h_1的数值分别为42.5kOe和80kOe。从M()ssbauer谱得到该非晶态合金系列的磁化强度与带面夹角随Co含量的增加而减小,表明了应力-磁致伸缩各向异性能随x增加而减小的变化规律。

Thermomagnetic measurements of the amorphous (Fe_(1-x)Co_x)_(78)Si_(9.5)B_(12.5) alloys were made on a magnetic balance in the temperature range from 77 to 1200K under the external field 12 kOe. Conventional Fe~(57) M()ssbauer spectroscopy in a transmission geometry was employed at room temperature. It was found that the average moment per magnetic atom in units of the Bohr magneton decreased from 2.1μ_B for Fe_(78)Si_(9.5)B_(12.5) alloy to 1.2μ_B for Co_(78)Si_(9.5)B_(12.5) with increasing Co content. The variation of T_C with transition metal content for a fixed metalloid composition may be described by the moecular field model. The average hyperfine field at Fe nucleus with increasing Co content of x up to 0.7 first increased from 250 to 278.5 kOe, and then decreased to 262 kOe for x=0.9. Assuming the magnetic moment μ_(Co) per Co atom is independent of content, it was obtained that the magnetic moment μ_(Fe) per Fe atom increased with increasing Co content and gradually approaches to the saturation value, which is 2.6μ_B for x=0.9. The relation between the average hyperfine field (■)_f and the average moment (■) per magnetic atom fol lows equation of (■)_f/(■)=h_0+h_1μ_(Fe)/(■). The values of h_0=42.5kOe and h_1=80kOe were given using the least squares method. It was obtained from M(■)ssbauer spectrum that the angle of magnetization with respect to the plane of the ribbon decreased with increasing Co content, showing the stress-anisotropy energy decreased with increasing Co content.

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