欢迎登录材料期刊网

材料期刊网

高级检索

对硅藻土进行氢氧化镁改性以提高它对印染废水中染料的吸附性能.采用原位沉淀法由MgCl2及NaOH在硅藻土上制备了氢氧化镁,并用SEM、XRD对改性材料进行了表征;用分光光度法研究了它对阴离子染料的吸附性能.结果显示:改性硅藻土的染料吸附能力比原硅藻土及氢氧化镁都高;染料的吸附等温线采用Langmuir及Freundlich模型拟合,结果表明改性硅藻土对染料的吸附更符合Freundlich模型.

The aim of this study is to improve adsorption performance of diatomite for the removal of anionic dye from textile wastewaters through modification with Mg(OH)2.MgCl2 and NaOH were mainly used to precipitate Mg(OH)2 into diatomite using liquid-phase precipitation method.The modified diatomite was characterized by XRD and SEM techniques.The adsorption performances of two acid(anionic)dyes onto absorbents were investigated employing spectrophotometric technique.It was found that the modified diatomite showed better adsorption capability than the initial diatomite and Mg(OH)2.Adsorption coverage over the surface of modified diatomite was studied using Langmuir's and Freundlich's models.The model parameters showed that the Freundlich model was better in simulation of the adsorption isotherm,suggesting some heterogeneity in the surface or pores of the diatomite.

参考文献

[1] Ramakrishna KR;Viraraghavan T .Dye removal using low cost adsorbents[J].Water Science and Technology,1997(2/3):189-196.
[2] Cooper P .[J].Journal of the Society of Dyers and Colourists,1993,109:97.
[3] Khraisheh M;Al-Ghouti M A;Allen S J .[J].Water Research,2005,39:922.
[4] Shawabheh R A;Tutunji M F .[J].Applied Clay Science,2003,24:111.
[5] Emin E C;Ramazan D .[J].Journal of Colloid and Interface Science,2005,282:314.
[6] Khraisheh M;Al-Ghouti M .[J].Adsorption-Journal of the International Adsorption Society,2005,11:547.
[7] Leentvaar J;Rebhun M .[J].Water Research,1982,16:655.
[8] Yang Yuxiang;Chen Rongsan;Dai Anbang .[J].Acta Chimica Sinica,1996,54:57.
[9] Yang Y X;Wu J D;Huang Z L et al.[J].Journal of Inorganic Biochemistry,1997,13(01):11.
[10] 杨玉香 et al.[J].南京大学学报(自然科学版),1991,27(04):706.
[11] Al-Qodah Z .[J].Water Research,2000,34(17):4295.
上一张 下一张
上一张 下一张
计量
  • 下载量()
  • 访问量()
文章评分
  • 您的评分:
  • 1
    0%
  • 2
    0%
  • 3
    0%
  • 4
    0%
  • 5
    0%