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根据沙钢对管线钢的生产需求及制造成本的控制,结合LF钢包精炼深脱硫的相关理论,开发了适用于管线钢的深脱硫精炼渣和低成本深脱硫工艺。使用该工艺,可完全不使用CaF2,只需使用石灰、铝脱氧产物和转炉下渣即可完成造渣,减少了石灰的消耗,降低了生产成本。180tLF生产实践表明:该工艺可将管线钢的硫含量稳定控制在10×10-6以下,精炼平均脱硫率高于85%。同时,该精炼渣具有较强的夹杂物吸附能力,精炼终点的非酸溶铝含量为(20~100)×10-6。

Based on the theory of desulphurization during LF refining,a novel fluorspar-free low melting point refining slag and low-cost desulphurization process was developed to optimize the desulphurization process and to reduce the cost during the refining process of pipeline steel.In this process,only lime,aluminium deoxidization production and BOF carryover slag were utilized for making LF refining slag,and therefore,the cost of LF desulphurization can be reduced.With this process for pipeline steel in 180 t LF,the final sulfur content was made stably less than 10×10-6,and the average desulphurization ratio was kept larger than 85%.Meanwhile,the insoluble aluminium content was(20-100)×10-6 after LF refining,indicating that the slag had good ability to absorb the inclusions.

参考文献

[1] 张彩军,蔡开科,袁伟霞,余志祥.管线钢的性能要求与炼钢生产特点[J].炼钢,2002(05):40-46.
[2] 王新华.适用于中厚板类钢种的合理炉外精炼工艺探讨[A].北京:冶金工业出版社,2008:14.
[3] Ogura Y;Kikuchi Y;Hasegawa T et al.Development of Secondary Refining Process and Its Application to Production of CleanStee[J].Tetsu To Hagane-Journal of the Iron and Steel Institute of Japan,1986,72(09):1309.
[4] M.M.Nzotta .Sulphide Capacities in Some Multi Component Slag Systems[J].ISIJ International,1998(11):1170-1179.
[5] M.M. Nzotta;Du Sichen .A study of the sulfide capacities of iron-oxide containing slags[J].Metallurgical and materials transactions. A, physical metallurgy and materials science,1999(5):909-920.
[6] Margareta A.T. .Application of the Sulphide Capacity Concept on High-basicityLadle Slags Used in Bearing-Steel Production[J].ISIJ International,1999(11):1140-1149.
[7] Ghosh A.Secondary Steelmaking:Principles and Applications[M].BocaRaton:CRCPress,2001
[8] 徐匡迪.关于洁净钢的若干基本问题[J].金属学报,2009(03):257-269.
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