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采用聚乙二醇(PEG)先与钙反应后,再与磷源溶液反应,在低温环境中制得无定形磷酸钙.借助XRD分析讨论了PEG∶CaCl2配比及PEG分子量与形成无定形磷酸钙之间的关系,实验结果表明,PEG∶CaCl2配比为1∶1和PEG分子量为10000是形成稳定无定形磷酸钙的最佳条件.其PEG稳定无定形磷酸钙的作用可理解为:在合成过程中PEG易存在于无定形磷酸钙Ca9(PO4)6团簇之间和吸附在无定形磷酸钙颗粒周围,有效地阻止了无定形磷酸钙向晶态的转变.

A stable amorphous calcium phosphate (ACP) was prepared by a wet chemical method at a low temperature in the presence of poly(ethylene glycol) (PEG). The effects of
PEG:CaCl2 ratios and the molecule weight of PEG on the stability of ACP in the aqueous solution were investigated. The results show that the optimized preparation conditions
for stable ACP are PEG:CaCl2 ratio of 1:1 and the PEG molecule weight of 10000. The role of PEG in stabilizing ACP in the aqueous solution is that PEG is easy to exist in the interstices between the ACP Ca9(PO4)6
clusters and adsorbed around ACP particles, and inhibits ACP transformations to crystalline hydroxyapatite.

参考文献

[1] Yohji I, Aya F, Mariko W. J. Biomat. Sci.: Polym. Ed., 1999, 10: 773--786.
[2] Linhart W, Peters F, Lehmann W, et al. J. Biomed. Mater. Res., 2001, 54: 162--171.
[3] Elliot J C. Studies in Inorganic Chemistry 18:Structure and Chemistry of the Apatites and Other calcium orthophosphates Elsevier, Inc., 1994. 53.
[4] Posner A S, Betts F. Accounts Chem. Res., 1975, 8: 273--281.
[5] Tadic D, Peters F, Epple M. Biomaterials, 2002, 23: 2553--2559.
[6] Skrtic D, Antonucci J M, Eanes E D, et al. J. Biomed. Mater. Res., 2002, 59: 597--604.
[7] Bertoni E, Bigi A, Falini G, et al. J. Mater. Chem., 1999, 9: 779--782.
[8] Liu Y, Wang W, Zhan Y, et al. Mater. Lett., 2002, 56: 496--501.
[9] 宋云京, 李木森, 温树林, 等, 电子显微学报, 2002, 21: 695--696.
[10] Saujanya C, Radhakrishnan S. Polymer, 2001, 42: 6723--6731.
[11] Tropp J, Blumenthal N C, Waugh J S. J. Am. Chem. Soc., 1983, 105: 22--26.
[12] Abbona F, Baronnet A. J. Cryst. Growth, 1996, 165: 98--105.
[13] Uekawa N, Sukegawa T, Kakegawa K, et al. J. Am. Ceram. Soc., 2002, 85: 329--334.
[14] 刘少华, 朱汉荣, 生物医学工程学杂志, 1990, 7: 329--332.
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